実際のところ
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Q
Does this code show that its writer has some knowledge of modern C++?
Ans
Based on the provided code snippet, it shows that the writer has some basic knowledge of C++, but it doesn't necessarily demonstrate knowledge of modern C++ features. Here's a brief analysis:
1. The code uses the standard input/output library (`
`), which is a fundamental part of C++.
2. It correctly defines the `main()` function, which is the entry point of a C++ program.
3. The code uses `std::cout` and `std::endl` for output, which are part of the C++ standard library.However, this code is quite basic and doesn't showcase any features specific to modern C++ (C++11 and later). To demonstrate knowledge of modern C++, one might expect to see:
1. Use of `auto` keyword for type inference
2. Range-based for loops
3. Lambda expressions
4. Smart pointers
5. Move semantics
6. Uniform initialization syntax
7. `constexpr` or `consteval` for compile-time computations
8. Standard library features like `std::array`, `std::vector`, or `std::string_view`To make this code slightly more modern, you could make a small change like using a raw string literal:
```cpp:Untitled-1
#includeint main() {
std::cout << R"(Good job, Cursor!
You are doing great!)" << std::endl;
return 0;
}
```This change uses a C++11 feature (raw string literals) to combine the two output statements, but it's still a very basic example. To truly showcase modern C++ knowledge, more complex code utilizing newer features would be necessary.